3q^2-120q=6300

Solution for 3q^2-120q=6300 equation:

3q^2-120q=6300

We move all terms to the left:

3q^2-120q-(6300)=0

a = 3; b = -120; c = -6300;
Δ = b2-4ac
Δ = -1202-4·3·(-6300)
Δ = 90000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{90000}=300$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-300}{2*3}=\frac{-180}{6}
=-30
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+300}{2*3}=\frac{420}{6}
=70
$